LinuxQuestions.org - [SOLVED] A question about strings...

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A question about strings...

This question is about C. Say I have a string 'test'. By looking at the chars we have { 't', 'e', 's', 't', '\0' }

Say I wanted to add a ': ' after it so that it becomes
{ 't', 'e', 's', 't', ':', ' ' }
I use the following code to implement this.

Code:

char str[16] = "test";

int len;

len = strlen(str);

len = len +2;

str[len - 2] = ':';

str[len - 1] = ' ';

str[len] = '\0';

So that should do it because the string is null-terminated. Yet when I run a

Code:

printf("%s", str);

Nothing gets printed. However, if I do the following instead

Code:

printf("%s\n", str);

It prints just fine. Why is that? I could always just do

Code:

write(STDOUT_FILENO, str, sizeof(str));

which works fine but I'd like to understand why printf without the newline prints nothing.

Quote:

Originally Posted by trist007 (Post 4344764)

Yet when I run a

Code:

printf("%s", str);

Nothing gets printed.

Usage of the \n in the printf() function will force the standard-out stream to be flushed. Since you haven't a newline above, the string is not printed. Practice with either of these:

Code:

printf("%s\n", str);

or with:

Code:

printf("%s", str);

printf("\n");

Btw, you could have saved yourself the trouble when augmenting the string using strncat().

Code:

strncat(str, ": ", sizeof(str));

Typically, however, one does not declare a string larger than necessary. Thus memory allocation comes into play. Read up the usage of malloc() and realloc(). You would need to declare a char pointer versus a char array when using these functions.

Thanks that explains it.