LinuxQuestions.org - [regExp] Retrieve content embedded in quotation marks

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sylvaticus

12-11-2007 05:47 AM

[regExp] Retrieve content embedded in quotation marks

Hello.. I need to retrieve a list of variables from a line of a programming language where variables are enclosed in quotation marks..

Eg.

Code:

MYVAR("AA","BB","CC")*1.12345*BVAR("DD","CC","EE") * 2

should retrieve me
AA BB CC DD CC EE

I am using python and up to now I arrived to write the following regexp:

Code:

variables = re.findall("\".+\"", myLine[i])

Hovewer I got

Code:

"AA","BB","CC")*1.12345*BVAR("DD","CC","EE"

How can I tell the regExp to get the more "internal" match ???

ghostdog74

12-11-2007 06:00 AM

there's no need to use regexp, you can make use of Python's basic string manipulation methods
eg ( tested only on that string)

Code:

s="""MYVAR("AA","BB","CC")*1.12345*BVAR("DD","CC","EE") * 2"""

while 1:

    try:

        ind = s.index('"')

        s=s[ind+1:]

        end = s.index('"')

        print s[:end]

        s=s[end+1:]

    except: break

output:

Code:

# ./test.py

AA

BB

CC

DD

CC

EE

however, if you are bent on using regexp

Code:

import re

pat = re.compile('"(.*?)"')

s="""MYVAR("AA","BB","CC")*1.12345*BVAR("DD","CC","EE") * 2"""

print pat.findall(s)

output:

Code:

# ./test.py

['AA', 'BB', 'CC', 'DD', 'CC', 'EE']

sylvaticus

12-11-2007 06:28 AM

Thank you very much. I was going in the direction of your fist example (using "split()" as I am a python-newby) before reading your text.

Following your text I learned that *? make the * operator to works in "minimal fashion" (from http://docs.python.org/lib/re-syntax.html ) that was my problem.

I suppose also that the quotation marks are not in the output because they are outside the () operator...

Thank you very much...

Antonello

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