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[Question] Check File existence

Hi, I'm trying to write s simple script, that will check if a file exists and echo if found or not. Here is a piece of the script.

Code:

#!/bin/bash

if [ "$#" -ne 1 ]; then

    echo "$(color ltgreen)usage: $(color off)$0 $(color ul)<argument>$(color off)";

else

if [  -e $1.tar.bz2 ]; then

    echo "$1.tar.bz2";

    exit 0

else

if [ ! -e $1.tar.bz2 ] && [ ! -e $1.tar.gz ]; then

    echo "$(color ltred).::ERROR::.$(color off):$(color ul)no$(color off) file found"

    exit 1

else

if [  -e $1.tar.bz2 ] && [  -e $1.tar.bz2 ]; then

    echo "Both Exist!!";

else

    echo "$1.tar.gz";

    exit 1

fi

fi

fi

fi

So what it basically does is to check if the user's input exists in a "tar.bz2" file or "tar.gz" file. It kinda works, but I noticed if a tar.bz & a tar.gz of the same name exist, it only outputs the tar.bz2 filename. Is there a simpler (or even better way to do this)

Well, if .tar.bz2 exists, it exits immediately... Maybe you should simply reorder your cases?

I think for this line,

Code:

if [ -e $1.tar.bz2 ] && [ -e $1.tar.bz2 ]; then

You meant,

Code:

if [ -e $1.tar.bz2 ] && [ -e $1.tar.gz ]; then

Possibly you should use 'elif' instead of 'else if', and also take a look at 'case';
http://www.faqs.org/docs/bashman/bashref_20.html#SEC20