[php] how to compare 2 arrays ?

graziano1968 · 11-21-2006, 01:07 AM

Hello

I am having problems comparing 2 arrays .

I have $domains[] which contains 3 values

123.com
456.com
789.com

and $data[] which contains 3 values arriving from a data file

566.com
789.com
555.com

I wish to compare the array $domains[] with array $data[] (each value of array $domains[] with
each value of $data[] ) . I wish to echo "OK" if two arrays are the same (==),
I wish to echo "FAIL" if the arrays are not the same.
So the result of the script should be

$domains[] compare result
123.com FAIL
456.com FAIL
789.com OK

I am trying in this way

Code:

...
...
$data_file = '/data.txt'; 
if (!empty($HTTP_POST_VARS['is_sent'])) process_form(); 
$data = file($data_file); 
$count_data = count($data); 

$countx=3;
for ($x = 0; $x < $countx; $x++)
{
  
echo"$domains[$x]";
for ($xc = 0; $xc <= $count_data-1 ; $xc++) 
{    
   $data[$xr] = trim($data[$xr]); 

if ( $domains[$x] == $data[$xc] )  {
echo "OK<br>";
# stop $xc for cycle because condition verified
$xr=$count_data;
}
else
{
echo "FAIL;
}
}
}

but it doesn't work ..

Is there a better way to do the work ?

Thank you!

zaichik · 11-21-2006, 06:06 AM

Your algorithm looks fine, but it appears that a variable you don't want has crept in to the code. Your inside loop counter is $xc, but then you have $xr in there out of nowhere. Sorry if I missed something obvious, but I'm not seeing where that gets its value.

If that is the issue, the result will be that your attempt to break out of the inner for loop will fail. Is that what you are getting?

graziano1968 · 11-21-2006, 07:30 AM

Quote:

Originally Posted by zaichik

Your algorithm looks fine, but it appears that a variable you don't want has crept in to the code. Your inside loop counter is $xc, but then you have $xr in there out of nowhere. Sorry if I missed something obvious, but I'm not seeing where that gets its value.

If that is the issue, the result will be that your attempt to break out of the inner for loop will fail. Is that what you are getting?

My code was not working because I had some space on the array (over the typo error you reported).
This was the solution

########################################
$data = array_map('trim', $data );
########################################

I found it on php.net (on a note) . I needed 4 hours to find this solution , and I have still to understand why "$data[$x]=str_replace(' ','',$data[$x]); " was not accepted (it didn't remove spaces from array) .

THANK YOU however