Hello,

I'm writing a script to create a filesystem layout on an AIX 5.1L Regatta using LVM. In this script I'm using a "for" loop to 'cat' a file and retrieve the filesystem name from the fourth field. The file I'm reading from looks like this:

VGName LVName LogName FileSystem LVSize

My forloop for the Filesystem looks like this:

for l in `cat layout.txt |cut -d" " -f4`
do FSN=$l
export $FSN
done

When I run the script it errors saying:
./Srwds.ksh[24]: /u02_01: is not an identifier

I know the slash (/) is the problem because if I remove them I do not get an error unless the filesystem I'm creating is something like opt/apps/somefile.

My question is how do I get around this? I need to create filesystems with absolute pathnames, and there are so many to create that putting them in a file and running the script is the best way to do it. Thanks for any and all suggestions.

Why are you calling export on the filesystem names? I think the export you are calling is the shell export for exporing shell variables. The filesystem names read from the file are not valid shell variables, so you are getting the error.

I'm exporting FSN={the filesystem name} (i.e., export FSN=/opt/games). I accidently put $FSN instead of just FSN for my variable name.

How many lines are there in your layout.txt? more than one?

for filesystem in `awk '{print $4}' layout.txt`; do
export FSN=$filesystem
done

Moses,

The file has about 15 lines that look like this:

u02rlvg u02rllv u02rllog /u02_01 8
u02rbvg u02rblv u02rblog /u02_02 8

etc....

What I want to do is use these entries to define my variables which will be put into commands like mklv, crfs and the like. I've also begun trying to write a perl script to do this because in the near future I'll be working with many more (30+) filesystems at a time.

Do it in Perl, if the above awk script doesn't work for you.

in the initial shell script, you should've used 'export FSN' instead of 'export $FSN'