shell script fo run auto job in cron
 

:newbie: :cry: I need to write a shell script that asks a user to input a single-line command that they want to have executed once a week. Ask the user to input the day of the week on which they want the command to be executed. I have submit their command as a correctly formatted cron job. Will this work?
#!/usr/bin/perl -w
use strict:
print "enter commnad to be run: ";
chomp (my $ command = <STDIN>
print "Enter the day of the week to run: ";
chomp (my $day = <STDIN>);
$day =~ tr/A-Z/a-z/;
unless ($day =~ /^(m|tu|w|th|f|sa|su)/) {
print "Error: You did not enter a valid week day\n";
exit 0:
}
if ($day =~/^m. *$/) {
$day = "mo";
}
if ($day =~ /^tu. *$/) {
$day = "tu";
}
if ($day =~ /^w. *$/) {
$day = "we";
}
if ($day =~ /^th.*$/) {
$day = "th";
}
if ($day =~ /^f.*$/) {
$day = "f";
}
if ($day =~ /^sa.*$/) {
$day = "sa";
}
if ($day =~ /^su.*$/) {
$day = "su";
}
my %week = ("su","0","m","1","tu","2","we","3","th","4","fr","5","sa","6");
open my $fh, ">/tmp/ctab" or die "$!";
print $fh "0*** $week{$day} $commnad \> \/dev\/null 2\>\$1\n";
close $fh;