[SOLVED] Using find with variables in shell script

mszabo · 05-01-2010, 10:35 AM

Hi,
I would like to know if find 4.4.0-2 can be used in a shell script to set the search location via a variable.
Can someone help, please?
I need to determine which files can be executed by anyone on paths given by $PATH.
I have found that:
find [location] -type f -perm /u=x,g=x,o=g
would be a good solution to turn to.
Now, I want to tokenize $PATH and supply each path via a variable [location]. Is it possible?
Marton

druuna · 05-01-2010, 11:53 AM

Hi,

Something like this maybe (one-liner):

for THIS_DIR in ${PATH//:/ }; do find ${THIS_DIR} -type f -perm /u=x,g=x,o=g; done

This will feed find all the path's that are inside the $PATH variable. If for example PATH=/bin:/usr/bin, find will be given /bin and then /usr/bin.

Hope this helps.

colucix · 05-01-2010, 01:36 PM

Actually the loop it's not necessary, since find can manage multiple paths at once:

Code:

find ${PATH//:/ } -type f -perm /u=x,g=x,o=g

mszabo · 05-01-2010, 02:51 PM

Quote:

Originally Posted by colucix

Actually the loop it's not necessary, since find can manage multiple paths at once:

Code:

find ${PATH//:/ } -type f -perm /u=x,g=x,o=g

Thanks, colucix! This worked!