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Old 03-02-2009, 11:00 PM   #1
Registered: Aug 2005
Posts: 298

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svn restore directory to a revision also removing files not part of revision

I have files in a working copy that's just for debugging purposes; I want to see how it looks like without all those random debugging files. Is there a way to put the directory in a state like I did a fresh checkout? E.g. removing files not part of repository and so forth?

Thank you
Old 03-03-2009, 05:18 PM   #2
Registered: Nov 2006
Location: Seattle, WA
Distribution: Fedora
Posts: 407

Rep: Reputation: 35
There are two ways to do this. Unless you *really* need to have the debugging directory in a clean state, the simplest is to check out a new copy of the project into a temp directory, and look at it there. You can delete the whole mess afterward, as the only information that you have a checked-out copy is kept in the directory tree of that checked-out copy.

To see what is in your debugging directory that is not part of the repository, use the command
$svn status
. This will display a (long) list of filenames preceded by various single-character symbols describing the state of those files. The ones with '?' before them are not part of the repository at all. Any with 'A' are also not part of the repository just yet, but if you commit they will be added.

Keep up the good practices; I use svn as a solo developer just so I can keep track of what I have released to clients, and can recover from my own bonehead errors.


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