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Old 09-02-2014, 03:32 AM   #1
PelleP
LQ Newbie
 
Registered: Aug 2014
Posts: 14

Rep: Reputation: Disabled
Simple but can't figure it out: print or store value from egrep statement


Hi!

Quick q:

I want to filter out only the location from a file path. I.e. getting only the string /root/ from
the string /root/file.db .
I do this using regexp, no problem. So if I have the file path text string in a file I'm getting what I want using:
Code:
egrep '^(.*[\\\/])' /path/to/file
which returns
/root/file.db with /root/ in red color.

But how the h**l do I extract that into a variable? If I use awk with the same regexp it prints the whole line.

And
Code:
var=$(egrep '^(.*[\\\/])' /path/to/file)
also stores the whole line into var.

Regards,
Pelle
 
Old 09-02-2014, 05:27 AM   #2
jensd
LQ Newbie
 
Registered: Jun 2014
Posts: 13

Rep: Reputation: Disabled
You can use dirname to do this:
Code:
dirname /root/test
/root
 
Old 09-02-2014, 05:41 AM   #3
PelleP
LQ Newbie
 
Registered: Aug 2014
Posts: 14

Original Poster
Rep: Reputation: Disabled
That was a much easier way!
Thanks a lot!

/P
 
  


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