Scripting: How to verifiy if input matches a range of numbers?

klss · 03-10-2009, 01:34 PM

Hi folks.

I am still trying to get myself into bash scripting and programming.
I guess below problem is a pretty simple issue for an experienced programmer.

How can I solve following issue? I'd like to check if an input fits
into a range of numbers, which are set by variables? I just couldn't figure it out by myself.

Below of course won't work. It's supposed to visualize what I would like to do.

THX

Code:

#!/bin/bash

number=0
rangestart=0
rangeend=100

while : ; do
read -p "Enter number: " number ; echo "$number"

case $number in
   [$rangestart-$rangeend]     ) echo "Hit"   ;;
                     *         ) echo "Blank" ;;
esac

done

exit 0

crabboy · 03-10-2009, 01:44 PM

There are a few different ways to do this, but this seems easiest to me:

Code:

#!/bin/sh

typeset -i num
rangestart=0
rangeend=100

while [ 1 ]; do
   read -p "Enter number: " num ; echo "$num"

   if [ $num -ge $rangestart ] && [ $num -le $rangeend  ]; then
     echo "Hit"
   else
     echo "miss"
   fi
done

klss · 03-11-2009, 02:44 AM

Well - your answer implies that it's not possible to apply a "case" construct for above example.

I hoped for a different solution.

THX

ak99505 · 03-11-2009, 04:57 AM

Quote:

Originally Posted by klss

Well - your answer implies that it's not possible to apply a "case" construct for above example.

I hoped for a different solution.

THX

in this example a case statement really wouldn't work, I suppose you could make it work, but that would
be a lot of effort.