run script error

ust · 09-02-2004, 08:36 PM

I try to run a new script on the RH linux shell , it always pop the sign "##4" to each line , but I can run the same script on other shell , what is wrong in my system ? please suggest , thx in advance.

____________________________

##4who -u
##4awk '{ print $6":"$7 }'
##4grep -v '\.'
_____________________________

serz · 09-02-2004, 08:41 PM

# are comments in bash scripting, so that won't work, at least in bash...

ust · 09-02-2004, 09:08 PM

I hv a line "#!/bin/bash" at the beginning of the script , but still not work , what can I do now ? please suggest , thx.

serz · 09-03-2004, 09:38 AM

Could you please post the whole script?

You need to remove those ###4...

Code:

#!/bin/bash

who -u
awk '{ print $6":"$7 }'
grep -v '\.'

ust · 09-06-2004, 01:58 AM

the script as below.

ust · 09-06-2004, 02:01 AM

#!/bin/bash

set -x
for user1 in `who -u | awk '{ print $6":"$7 }' | grep -v "\."| awk -F : '{ print
($1*60)+$2":"$3 }'`

do

time=`echo $user1 | awk -F ":" '{ print $1 }'`
pid=`echo $user1 | awk -F ":" '{ print $2 }'`

if [[ $time -gt 360 ]]
then
kill -9 $pid
fi
done

ust · 09-06-2004, 10:54 AM

what is wrong with the script ? please advise , thx

ust · 09-09-2004, 08:44 AM

I still can't hv the error , could suggest what is wrong with my script ? thx.