Redirecting grep output to a variable

dimako83 · 11-17-2008, 06:48 AM

Hi,

I am trying to redirect grep count ("grep -wc") output to a variable but I cant succeed:

the command Im running is:

[root@***]# set var1temp
[root@***]# $var1temp = `cat 2008_11_15_1226700018.log | grep "clean" -wc`

and I receive the next error:
bash: =: command not found

Could you please help me to understand what is wrong with the command?

Thank You.

colucix · 11-17-2008, 06:57 AM

Quote:

Originally Posted by dimako83

[root@***]# $var1temp = `cat 2008_11_15_1226700018.log | grep "clean" -wc`

To assign a variable the correct syntax is

Code:

variable_name=something

that is: don't put the $ sign in front of the variable name. You use $variable_name when you have to retrieve the actual value of the variable.

dimako83 · 11-17-2008, 07:07 AM

but then I get this error:
bash: var1temp: command not found

colucix · 11-17-2008, 07:09 AM

Quote:

Originally Posted by dimako83

but then I get this error:
bash: var1temp: command not found

Either don't put blank spaces around the = sign.

syg00 · 11-17-2008, 07:13 AM

Not if you do it properly - seems you have a liking for imbedded spaces.

<Edit:> too slow ...

dimako83 · 11-17-2008, 07:23 AM

It works now! Thank you!

I knew it was something stupid.... sorry for bothering you with such a stupid issue, well thank you again!

colucix · 11-17-2008, 08:22 AM

Quote:

Originally Posted by dimako83

It works now! Thank you!

I knew it was something stupid.... sorry for bothering you with such a stupid issue, well thank you again!

If you're new to linux or to shell programming, no question is stupid! An answer can be, anyway!