I am trying to run a .sh script in bash. The script skips the first 'read' and stops at the second read in the script. Has anyone had this problem with Redhat/bash before? If so, did you find a fix.
Thanks,
jh111451

can you post that script

You don't necessarily have to post the whole script---but you have to give us some kind of information. For example, when you refer to the first and second read, is this in a loop?

The script is stopping at the first read but is storing the entered value in the variable associated with the second read (ln).
The script does not stop and prompt you to enter the last name or address.
I am running the script on as server. I am connected thru secure-shell.
Logged in as 'oracle' user.

Here is a test script I have been working with:
1 read -p "enter first name " -a fn;
2 echo "fn is " $fn;
3
4 printf "\n";
5 read -p "enter last name " -a ln;
6 printf "\n";
7 echo "ln is " $ln;
8
9 printf "\n";
10 read -p "enter address " -a ad;
11 printf "\n";
12 echo "ad is " $ad;
13
14 exit


Here is the result:
enter first name john

fn is

enter last name
ln is john

enter address
ad is

Well, that script works fine for me (assuming you don't actually have line nums )