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Old 09-12-2014, 02:43 PM   #1
trapfether
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Registered: Sep 2014
Posts: 2

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Question program aborted while freeing variable from memory


when debugging my program i receive this error from GDB

Program received signal SIGABRT, Aborted.

it happens at this line in my code

free((int *)ptr);

ptr is a void pointer that is indeed pointing to an integer. stepping through the program i find that even at this line (immediately proceeding it's execution) the pointer value can still be read correctly with explore value (int *)ptr. I have also checked to make sure that ptr was not accidentally set to the position of a variable actually declared in my program and i found that it was not. I am completely stumped at this point any help would be very appreciated.
 
Old 09-12-2014, 03:40 PM   #2
trapfether
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Registered: Sep 2014
Posts: 2

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I found the culprit

int in = (*blockPtr).count;
for(;in > (*blockPtr).count - l + index; in--)
{
((void **)(*blockPtr).array)[in] = ((void **)(*blockPtr).array)[in-1];
}


here i shift all elements to the right in a non-full array that fall past a target index within that array.
However, i left out the following line which is meant to assign the target index with a new pointer value in order to perform an "insertion" operation.

((void **)(*blockPtr).array)[in] = newptr;

since i did not reassign that index, i had two indices pointing to the same position in memory which caused me to double free a spot in memory. Hopefully my mistake will help someone else fix theirs.

Last edited by trapfether; 09-12-2014 at 03:41 PM.
 
  


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