Need help with a simple script shell script

WindowBreaker · 12-15-2005, 11:49 AM

I need a simple shell script that can autoincrement numbers, starting at one (001), thru 999.
The catch: the preceding zero's are required.

Here's what I've got:

#!/bin/sh
num=001
while [ $num -lt 1000 ];do
echo $num
num=$(($num+001))
done

This results in the following output:
001
2
3
4
5
6
7. . .etc

Is there a simple way to cause it to output, and not truncate, the leading zeros???

I'm sure it's something simple, but this is driving me nuts, so any suggestions would be appreciated.

Thanks

druuna · 12-15-2005, 12:09 PM

Hi,

Do you have to do this with a script?

If so:

Use printf instead of echo

printf "%03g\n" $num

If not: take a look at seq

Examples:

$ seq 5
1
2
3
4
5
$ seq 3 5
3
4
5
$ seq -f "%03g" 3 5
003
004
005

Hope this helps.

homey · 12-15-2005, 12:45 PM

How about something like this

Code:

#!/bin/bash

for (( i=1; i<1000; i++ )) ; do
if [ $i -lt 10 ]; then
   echo 00$i
elif [ $i -ge 10 -a $i -lt 100 ]; then
   echo 0$i
else
   echo $i
fi
done