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Old 09-02-2003, 03:06 PM   #1
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Mozilla Firebird

I just downloaded and unzipped the MozillaFirebird executable. I placed the mozillaFirebird directory containing the executable in


How do I change my path to recognize the localtion of the executable, which is /usr/local/MozillaFirebird/MozillaFirebird.exe ???

I'm running SUSE Pro 8.2

Any help woudl be greatly appreciated.

Also, I was wondering if there was a way to set your path so that you dont' have to type ./ infront of every file you want to execute.

Old 09-02-2003, 03:13 PM   #2
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bet you $10,000 it's not MozillaFirebird.exe.... this ain't windows....

normally you would just create a symlink from the MozillaFirebird directory to a suitable location already on your path... e.g.

ln -s /usr/local/MozillaFirebird/MozillaFirebird /usr/local/bin/firebird

but you can always edit a local file like /home/you/.bashrc (i.e for your user only) to add something like..

export $PATH=$PATH:/usr/local/MozillaFirebird
Old 09-02-2003, 03:15 PM   #3
Registered: Aug 2003
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this may not be the best way to do it, but you could create a symbolic link in the /sbin (which is a default path)

ln -s /usr/local/MozilliaFirebird/mozillafirebird firebird

then when you type firebird from the console it will execute.
Old 09-02-2003, 03:18 PM   #4
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acid_kewpie thanks for correcting me....I've used linux on and off for a little bit, but now I've decided to use it as my primary OS. It's hard to break old habits
Old 09-02-2003, 03:25 PM   #5
Registered: Aug 2003
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acid's advice is absolutely correct on this one...

i will add that if you REALLY want to be able to execute files all over and run into problems with path, you COULD append your path to include your current working directory such as


then, as long as the file is in your current working directory, whatever that may be, you can execute the file.

**note: i have heard that this is not a very sound decision from a strict security standpoint, but it's your decision, a lot of people do it.
Old 09-02-2003, 03:27 PM   #6
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I went into my .bashrc file and added the following line:

export $PATH=$PATH:/usr/local/MozillaFirebird

Now when a new shell opens, I'm getting the following error:

bash: export: `/usr/local/bin:/usr/bin:/usr/X11R6/bin:/bin:/usr/games:/opt/gnome2/bin:/opt/gnome/bin:/opt/kde3/bin:/usr/lib/java/jre/bin:/opt/gnome/bin=/usr/local/bin:/usr/bin:/usr/X11R6/bin:/bin:/usr/games:/opt/gnome2/bin:/opt/gnome/bin:/opt/kde3/bin:/usr/lib/java/jre/bin:/opt/gnome/bin:/usr/local/MozillaFirebird': not a valid identifier

Any thoughts on what I'm doing wrong..sorry about these petty questions.

Old 09-02-2003, 08:46 PM   #7
Registered: Aug 2001
Location: New Hampshire, USA
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export PATH=$PATH:/usr/local/MozillaFirebird

no $ in front of the first PATH


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