(include_path='.:/usr/share/pear) ????

bentman78 · 07-11-2003, 08:12 AM

I am farily new to PHP, but getting the hang of it. However this one is stumping me:

Warning: Failed opening 'zina/index.php' for inclusion (include_path='.:/usr/share/pear')

What does this mean? How do I fix it? I would appreciate any help.

What I am trying to do is include a PHP into another one and am getting this error. Thank you

cnjohnson · 07-11-2003, 11:10 AM

I have good news and bad news. The good news is that it mean zina/index.php could not be found by looking in two places: the current working directory (that is what the . means) nor could it be found in /usr/share/pear. The colon : is simply the separator character for the seach path.

The bad news is that I am cluless about fixing it, other that to tell you to find "zina/index.php' and put it in /usr/share/pear/

Cheers--
Charles

bentman78 · 07-11-2003, 02:09 PM

Thank you very much...I will try that out.