How to stop a real time process in a script

susee_sundar · 05-30-2006, 06:36 AM

Hi All.,

I want to monitor the log file by grepping two patterns..
The log file is a real time one, which gets updated in every second..
i am using the following command to grep the pattern at its end..

$
$tail -f logfile | grep pattern1
[ctrl+c]
$tail -f logfile | grep pattern2
[ctrl+c]
$

But when I write a script to do it automatically
script content:-
!#/bin/sh
tail -f logfile | grep pattern1
tail -f logfile | grep pattern2
end

The script starts grepping the pattern1 fine..
But How can I make an interrupt fuction to stop it and make the shell to move to the next command..
If I Press CTRL+C

The Script ends and came back to the shell prompt..
If Anybody already faced the problem are knows the solution share me the same...
Waiting for the reply..

Regards
Suseendran .A

marozsas · 05-30-2006, 06:57 AM

Put the first command in background, then the second can start in parallel.

Code:

#!/bin/bash
tail -f logfile | grep pattern1 &
tail -f logfile | grep pattern2

marozsas · 05-30-2006, 07:10 AM

of course, if logfile is the same, you can search for several patterns in one single command

Code:

tail -f logfile | grep -E "pattern1|pattern2|pattern3"

susee_sundar · 05-30-2006, 07:17 AM

The operation it is doing is fine..

But the hidden job is not getting killed even after the end os script..

i didnt get my prompt back and the grep pattern is displayed continuously for the hidden command.

regards
Suseendran .A

susee_sundar · 05-30-2006, 07:20 AM

tail -f logfile | grep -E "pattern1|pattern2|pattern3"

Thank YOU for the Code
It is working fine.....

Regds
SUSEENDRAN .A