advanced regular expression in vi
thanks, but it's not satisfactionary (?!) answer, because I have to replace only these dots which are neighbours of the numbers.
for example : '12.45' should be replaced to '12,45' , '26.3' to '26,3' etc. ; but the result of 'linux.com' should not be 'linux,com' ! (no changes in this example !)
I have to use an advanced regular expression, but I don't know how
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