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Old 04-03-2006, 05:35 AM   #1
gandi71
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Registered: Apr 2006
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how to replace numbers in vi ?


i have to change all numbers in the text in vi like this xxx.xxx --> xxx,xxx

how to do it in one-line command ?
 
Old 04-03-2006, 05:44 AM   #2
Pavan mahoorker
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Registered: Sep 2004
Location: Bangalore
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Hi,
First come out of your insert or append mode in vi by presseing the Esc button then type as below.
:%s/xxx.xxx/xxx,xxx the enter key
And if you want to replace every where then use :%s/xxx.xxx/xxx,xxx/g
 
Old 04-03-2006, 03:42 PM   #3
gandi71
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Registered: Apr 2006
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advanced regular expression in vi

thanks, but it's not satisfactionary (?!) answer, because I have to replace only these dots which are neighbours of the numbers.

for example : '12.45' should be replaced to '12,45' , '26.3' to '26,3' etc. ; but the result of 'linux.com' should not be 'linux,com' ! (no changes in this example !)

I have to use an advanced regular expression, but I don't know how
 
Old 04-03-2006, 03:49 PM   #4
linuxChique
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Registered: Apr 2003
Location: Huntsville, AL
Distribution: mandrake
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use something like:

Code:
:%s/\(\d\)\.\(\d\)/\1\,\2/g
 
Old 04-03-2006, 04:31 PM   #5
gandi71
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Registered: Apr 2006
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it's really works !

thanks for you , 2 points for me
 
  


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