hello
i am trying to write a regular expression that scan a log file using and returns all the lines that have the word "ERROR" in them...

i am using a program called logsurfer; but regexp are very difficult for me to understand

so i tried this,

i have lines in the log file that look like this :

12:47:36,487 ERROR [smb.protocol.auth] No valid CIFS authentication combination
available
12:47:36,487 ERROR [smb.protocol.auth] Either enable Kerberos support or use an
authentication component that supports MD4 hashed passwords
12:47:36,491 ERROR [alfresco.smb.protocol] CIFS server configuration error, Inva
lid CIFS authenticator configuration
org.alfresco.error.AlfrescoRuntimeException: Invalid CIFS authenticator configur
ation


I have to write a regex that scans the file finds the lines with ERROR and reports the whole line.

i tried doing this :
".*[ERROR].*"

is this regex correct; will it return all the lines that have the word error in the logfile. there are lines of the file that doesn't have this word and they can be ignored.

if you can provide me any help of hints i'll be greatly grateful.

thank you in advance;

Maybe I'm missing something, but does not a simple grep do what you're trying to do?
Edit: oops... sorry, I just noticed you are using a program called logsurfer to do that. Well... usually a regular expression is embedded in slashes, not square brackets. Maybe you are simply looking for
whereas square brackets in a pattern mean a character list, that is not the whole word "ERROR" but a list of single characters "E", "R", "O" with "R" repeated 3 times. Unless logsurfer has its own syntax, but sincerely I doubt it...

If that fails, tryDave

thank you for your help
i tried "\<ERROR\>" it seems to work.