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Old 11-28-2006, 10:38 PM   #1
mathfeel
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Registered: Feb 2002
Distribution: Gentoo
Posts: 95

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grep regexp question


I am trying to extract a column from a command-separated table. How do I use grep or egrep or sed or whatever tool to extract the text (unicode, contain Chinese character sometimes) between says, the n-th and the (n+1)-th comma?

Last edited by mathfeel; 11-28-2006 at 10:39 PM.
 
Old 11-28-2006, 10:55 PM   #2
finegan
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Registered: Aug 2001
Location: Dublin, Ireland
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You're looking for "cut" You can declare an arbitrary delimeter with -d.

Here's an example:

Code:
fin@sleepy:~$ cat foo
bob,jack, tom, ed
bob,  jack, tom, ed
bob,   jack, tom, ed
bob, mike, jack, tom, ed
bob, coffee,  jack, tom, ed

fin@sleepy:~$ cat foo | cut -d , -f2-3
jack, tom
  jack, tom
   jack, tom
 mike, jack
 coffee,  jack

or...

fin@sleepy:~$ cat foo | cut -d , -f1-3
bob,jack, tom
bob,  jack, tom
bob,   jack, tom
bob, mike, jack
bob, coffee,  jack
Where -f controls the fields you want outputted.

Is that what you were lookin for?

Cheers,

Finegan
 
  


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