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Old 03-09-2004, 10:49 AM   #1
Registered: Oct 2003
Location: Grand Forks, ND
Distribution: Suse/Slackware/RH
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grep (not)

Is there a way to grep all lines that do NOT have somethign in them?

So if I had lines:

#Hi my name is
Blah Blah
#ok thanks

And I want to grep the file to only display all lines that don't have a # in them is that possible? And if so what is the command to do it?
Old 03-09-2004, 11:02 AM   #2
Registered: Jun 2003
Location: Ontario
Distribution: Ubuntu, Gentoo, Debian
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From man grep:

-v, --invert-match
Invert the sense of matching, to select non-matching lines.

so, to find lines that do NOT contain "foo":
grep -v foo


If you have a question, please check these in this order:

man and info pages for relevant commands
documentation that came with the program for a relevant HOWTO
Google and LinuxQuestions forum searches
THEN post a question if you can't find the answer.
Old 03-09-2004, 11:03 AM   #3
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Here's an example. You need to escape the # because it's a special character.

cat test.txt | grep -v "#"
Old 03-09-2004, 11:05 AM   #4
Registered: Feb 2004
Location: Sacramento, CA
Distribution: Slack 9.1, slackware-current
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Originally posted by Rounan
From man grep:

-v, --invert-match
Invert the sense of matching, to select non-matching lines.

so, to find lines that do NOT contain "foo":
grep -v foo


note that # is a special character & needs to be escaped. <edit> or quoted.

grep -v \#  filename

Last edited by bnice; 03-09-2004 at 11:07 AM.


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