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alenD

04-14-2008 10:06 AM

bash script to preserve only first digits

Hello

I have a big number - i am looking for a bash script to preserve only first 3 digits of that number (basically, to have another number that consists only of first 3 digits of the original number)

thanks in advance

H_TeXMeX_H

04-14-2008 11:00 AM

for example:

Code:

echo '1234567890' | cut -c1-3

shadowsnipes

04-14-2008 11:08 AM

Try using cut -b-3

Example

Code:

echo "12345" | cut -b-3

123

alenD

04-14-2008 11:36 AM

great. thnx

unSpawn

04-14-2008 12:22 PM

s=1234567890; s=${s:0:3}

colucix

04-14-2008 12:24 PM

Merely in bash

Code:

number=1234567890

short_number=${number:0:3}

Edit: moderators are always faster... ;)

unSpawn

04-14-2008 12:51 PM

Yeah, but your answer is more complete in mentioning it only works in BaSH-like shells. BTW, how's the NuFW/Network auth project going?

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