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how to use python scripts to simulate the login?

how to use python scripts to simulate the login? below is my php website code,
login.html:

Code:

<html> 

<body> 

<meta http-equiv="Content-Type" content="text/html; charset=utf-8">

<form name="login" action="login1.php" method="POST">  

name<input type="text" name="name"/> 

<p>password<input type="password" name="password"/> </p> 

<input name="log" type="submit" value="login"> 

</form> 

</body> 

</html>

login1.php:

Code:

<meta http-equiv="Content-Type" content="text/html; charset=utf-8">

<?php 





$mysqli=mysqli_connect("localhost","root","root","logindb");

$name=$_POST["name"]; 

$passowrd=$_POST["password"]; 

//print_r($_COOKIE);



if ($name && $passowrd){ 

$sql = "SELECT * FROM test1 WHERE name='$name' and password='$passowrd'"; 

$res = mysqli_query($mysqli,$sql); 

$rows=mysqli_num_rows($res); 

if($rows){ 

//header("location:login1.php"); 

//exit; 

echo "successful";





}

 else{

echo "failed，please check username and password！";

}

mysqli_free_result($res);

mysqli_close($mysqli);

}

?>

I can visit http://127.0.0.1/gongji/login/login.html to the website code.

i want to simulate login and it can reponse me success or failure? but

i try to use below python scripts,but it did not response success or fialure to me.how to modify it?

Code:

#coding:utf-8

import urllib

import urllib2



aa = {'user':'knight','pasword':'knight'}

cc = urllib.urlencode(aa)

#print "this is %s" %(cc)



url = 'http://127.0.0.1/gongji/login/login.html' 

#print url 

print urllib2.urlopen(url,cc).read()

Hi!

Not really sure what you are trying to do here. First of all, you are not sending any POST requests with your Python script.

I suggest that you A) Use Python 3 in conjunction with requests, and B) Check this link for further information:
http://stackoverflow.com/questions/1...d-post-request

Furthermore, here's an example of how I would read a web page in Python 3 with urllib:

Code:

>>> import urllib.request

>>> data = urllib.request.urlopen("http://google.com")

>>> raw_Html = wp.read()

>>> print(raw_Html)

But, seriously, don't. Use requests instead, you will thank me later...

Best regards,
HMW

Quote:

Originally Posted by HMW (Post 5509039)

Code:

>>> import urllib.request

>>> data = urllib.request.urlopen("http://google.com")

>>> raw_Html = wp.read()

>>> print(raw_Html)

But, seriously, don't. Use requests instead, you will thank me later...

Best regards,
HMW

i want to the website can respons me login access or login failure。
finaly i want to check the login is unnormal or normal.
i try to modify it this:(but no matter the username and password is right or wrong) it print sucess.

Code:

#coding:utf-8

import urllib

url = 'http://127.0.0.1/gongji/login/login.html'





data = {'name':'knight',

        'password':'knight'

        }





post_data = urllib.urlencode(data)





try :

    f  = urllib.urlopen(url, post_data)

except:

    print "login success"

else:

    print "failure"

Quote:

Originally Posted by 624867243@qq.com (Post 5509306)

i try to modify it this:(but no matter the username and password is right or wrong) it print sucess.

Code:

#coding:utf-8

import urllib

url = 'http://127.0.0.1/gongji/login/login.html'





data = {'name':'knight',

        'password':'knight'

        }





post_data = urllib.urlencode(data)





try :

    f  = urllib.urlopen(url, post_data)

except:

    print "login success"

else:

    print "failure"

That is because your logic behind Python's exceptions is plain wrong.
Read more here:
http://www.python-course.eu/python3_...n_handling.php

Basically, your code ALWAYS throws an exception, therefore you will ALWAYS get
login success
as a result.

If you need to use Python for this, you're gonna have to learn the language. There is (in my view) an excellent course (free) here:
http://www.pythonlearn.com/html-009/

Best regards,
HMW