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Old 05-02-2016, 05:40 AM   #1
llee4131
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Xargs problem


I have no files on my current directory and three sub directories.

If I do
find . -maxdepth 0 -type f
predictably there is no output since there are no files.

But if I do
find . -maxdepth 0 -type f | xargs ls -isl
this produces list of the three sub directories.

I clearly stated -type f so why is this listing the sub directories?
 
Old 05-02-2016, 06:05 AM   #2
wpeckham
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Things do exactly what they are designed to. darn it!

Since the find is generating an empty list, xargs receives the empty list and runs the ls against it. Think: what does the ls command return if run in that folder without additional parameters?
 
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Old 05-02-2016, 06:16 AM   #3
hydrurga
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find . -maxdepth 0 -type f | xargs -r ls -isl

-r: If the standard input does not contain any nonblanks, do not run the command.
 
Old 05-02-2016, 06:21 AM   #4
llee4131
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nice!
 
Old 05-02-2016, 07:04 AM   #5
Turbocapitalist
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Quote:
Originally Posted by wpeckham View Post
Since the find is generating an empty list, xargs receives the empty list and runs the ls against it. Think: what does the ls command return if run in that folder without additional parameters?
You can see this more clearly if you run xargs a few times with the -t option using different input.
 
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Old 05-02-2016, 07:11 AM   #6
MadeInGermany
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Like xargs -r but safer regarding special characters in filenames is
Code:
find . -maxdepth 1 -type f -exec ls -isl {} +
 
  


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