Whats wrong with this syntax?

AsherSevyn · 11-30-2012, 12:20 PM

/usr/local/apache2/bin$ pwd /usr/local/apache2/bin

unSpawn · 11-30-2012, 12:36 PM

Seen 'man pwd'?

David the H. · 11-30-2012, 12:45 PM

Or even help pwd, since you're most likely using the bash built-in version.

(hint: what arguments does it take?)

AsherSevyn · 11-30-2012, 02:11 PM

I've read the man page. Doesn't make sense as to why this isn't working to me.

unSpawn · 11-30-2012, 02:30 PM

It works perfectly as it it just disregards the directory you gave and prints the current/working directory.

David the H. · 12-02-2012, 11:54 AM

What you need to do then is tell us how, exactly, it's not working. What is it doing that you think it shouldn't, or not doing that you think it should? What is the exact output you get when you run it? And if you aren't using bash, what is the environment you're running it in?

It's pretty hard to tell you why something isn't working if you don't provide any information to diagnose the problem with.

Wim Sturkenboom · 12-03-2012, 03:24 AM

Quote:

Originally Posted by AsherSevyn

I've read the man page. Doesn't make sense as to why this isn't working to me.

As David the H. says, tell us what you expect it to do. "it isn't working" means nothing.

RaviTezu · 12-03-2012, 04:11 AM

What are you trying to do with pwd(print working directory)?

Habitual · 12-03-2012, 05:47 AM

Quote:

Doesn't make sense as to why this isn't working to me.

Read it again.

Code:

PWD(1)                                          User Commands                                          PWD(1)

NAME
       pwd - print name of current/working directory

It only does ONE THING, print name of current/working directory.