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12-18-2007, 01:46 PM
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#1
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LQ Newbie
Registered: Nov 2007
Posts: 2
Rep:
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What does the $@ represent in a bash script?
I'm new to reading (and writing) bash scripts and I can't find any documentation for what the $@ parameter/variable represents and what value it receives. Please advise. Thanks.
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12-18-2007, 02:18 PM
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#2
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Senior Member
Registered: Oct 2005
Location: UK
Distribution: Slackware
Posts: 1,847
Rep: 
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Quote:
Originally Posted by man bash
@ Expands to the positional parameters, starting from one. When the
expansion occurs within double quotes, each parameter expands to a
separate word. That is, "$@" is equivalent to "$1" "$2" ... If
the double-quoted expansion occurs within a word, the expansion of
the first parameter is joined with the beginning part of the orig-
inal word, and the expansion of the last parameter is joined with
the last part of the original word. When there are no positional
parameters, "$@" and $@ expand to nothing (i.e., they are
removed).
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It means each argument supplied to the script from the command line:
Code:
pwc101@linux:> ./myscript argument_1 argument_2
$@ represents argument_1 and argument_2 in that example, which can be individually referenced as $1 and $2.
See http://db.ilug-bom.org.in/Documentat...es.html#APPREF for more info.
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12-18-2007, 06:37 PM
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#3
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LQ Newbie
Registered: Nov 2007
Posts: 2
Original Poster
Rep:
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Thanks
for the help!
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12-18-2007, 06:51 PM
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#4
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Senior Member
Registered: Dec 2004
Location: Olympia, WA, USA
Distribution: Fedora, (K)Ubuntu
Posts: 4,187
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On most distributions the info command (in a terminal window) may be used to display information about a command. Did you try info bash?
If you're not familiar with the info command, try info info for an explanation.
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12-18-2007, 10:56 PM
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#5
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LQ Guru
Registered: Aug 2004
Location: Sydney
Distribution: Rocky 9.x
Posts: 18,444
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