variable substitution results in "command not found" error
 

find /data/backup/ -name 20140202* -exec awk -F"|" '$23!=0 {print"|"$14"|"$23}' {} \; > Day1.txt

host='XX.XX.XX.XX'
user='root'
passwd='root'
(
echo "$user"
echo "$passwd"
echo "cd /data/"

echo "find /data/backup/ -name rec20140202* -exec awk -F"|" '$23!=0 {print"|"$14"|"$23}' {} \; > Day2.txt"

echo "exit" )| telnet "$host"

===========================
in the above code fragment second find command ( inside telnet part)is not working. I am getting an error as below
===========================
server2:/data # testnew.sh: line 27: '3!=0 {print: command not found
testnew.sh: line 27: 4: command not found
testnew.sh: line 27: 3: command not found
testnew.sh: line 27: }' {} \; > Day2.txt: command not found
Connection closed by foreign host.

Pls help

Look carefully at that line, check the double-quotes!
What you want is to wrap the whole line in double-quotes, but actually the first enclosed is "find /data/backup/ -name rec20140202* -exec awk -F"

Thank you very much pingu!

Use of escape (\) preceding character for (") and ($) has solved the issue.

Regards,

- Sharath