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Old 03-01-2011, 10:34 PM   #1
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I have a big file called the game, and want to find all the lines that do NOT have the word "shozbot" in it, and I want to sort them alphabetically, and save that in a file called "squiggy". How would I do that in one line of commands?

Old 03-01-2011, 10:42 PM   #2
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Sorry, but it's hard to take your post seriously - with a subject of urgent and a task that sounds like it was made up... What have you done so far and what specific problem are you having?
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Old 03-02-2011, 08:29 AM   #3
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Seriously, pick a more appropriate title for your post next time.

As for the command, here's a basic example (you'll need to add options depending on your requirements):
grep -v shozbot game.txt | sort > squiggy.txt

Last edited by win32sux; 03-02-2011 at 08:30 AM.
Old 03-02-2011, 08:45 AM   #4
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Win32sux has answered your question.

I give you some explanation here.

grep -v "pattern" fileName
prints lines that do not caontain the "pattern". If the "pattern" is not found at all then all the lines are printed.

Remove the -v option and it will print only those lines that contain at least one match of the "pattern".


grep -v "shozbot" game
will print any line that does not contain "shozbot".

Next, we pipe this output to the sort command which displays the sorted lines:

grep -v "shozbot" game | sort
Finally, we redirect the sorted output to a named file:

grep -v "shozbot" game | sort > squiggy
Check it out!


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