[SOLVED] Trying to figure out a date command

thebeav · 01-13-2011, 04:55 PM

Newbieness glaring brightly here

Working through a Unix/Linux book trying to figure out the basics of the shell. I am trying to figure out how to run a command with bash to find the last day of the month in any given month. I read the man pages for date and cal but I am stupid or missing something. I figured out many things but this is the only one that has me pulling my hair out at this time. Thanks in advance.

tligda · 01-13-2011, 07:14 PM

Quote:

cal <month> <year> | sed '/^$/d' | tail -1 | awk '{printf $NF}'

via

jmc1987 · 01-13-2011, 09:21 PM

Well what is it your trying to get? This is a example using the date command with a backup

tar cvzpf homebackup-`date +%m-%d-%y` /home/username

If you noticed I put the date command in ``. So give a little more info if this doesn't cover what you need

crts · 01-13-2011, 09:54 PM

Hi,

this, e.g., will also give you the name of the day:

Code:

cal feb 2000|sort -nr | awk 'FNR==1{a=NF;b=$NF}/^[^ [:digit:]]/{print $a,b}'

If this is not what you were looking for then you'll need to clarify a bit more.

thebeav · 01-13-2011, 10:31 PM

Thank you, now I have to digest this. Thanks for the help. Much appreciated.

for the last day of October

Code:

echo $(cal 10 2011) | awk '{print $NF}'

for the last day with of October including name of the day

Code:

cal 10 2011|sort -nr | awk 'FNR==1{a=NF;b=$NF}/^[^ [:digit:]]/{print $a,b}'

jmc1987 · 01-13-2011, 11:56 PM

oops sorry OP i just realized I had misread your question.