stupid makefile question
 

i dont know why this is doing this. i have a makefile setup to run...

compiler = /usr/bin/g++

compilerflags = -ansi -Wall

OBJECTS = driver.o

driver: driver.o
$(compiler) $(compilerflags) -o driver driver.o

driver.o: driver.c /usr/include/driver.h
$(compiler) $(compilerflags) -c driver.c

it compiles and i get driver as the executable.

but how do i run it? it's been a while for me and i get

bash: driver: command not found when i type in driver

any ideas? :(

./driver . (the current directory) usually isn't in your $PATH, so you have to specify it explicitly.

im not sure what you mean...

How about the command: make driver

that gives me the same thing, i already have the target as driver

What btmiller means is that instead of typing
driver<enter>
you should use
./driver<enter>
because in Linux by default executables are
only picked when they can be found in the
directories that the path variable points at
echo $PATH
for a test ... alternatively, you can use a
qualified filename to run it, e.g.
/home/user/src/mypackage/driver
or a shorthand that contains a reference to
a directory, e.g.
~/mypackage/driver
or, as suggested above,
./driver

[edit]
For more detail have a look at the output of
ls -la
in a not too full directory... at the top of the listing
you'll see something like
Note the top two entries in the listing. They refer
to the current directory (.) and the parent directory (..)
[/edit]





Cheers,
Tink