Show a certain line in file
 

Hi everyone,

I have a very big text file with over 100 million rows. I want to look at rows 36,000,000 through 36,000,005 for example, how would I do that using the command line? Thanks.

sed -n '36000000,36000005P' <logfile>

I am pretty sure that sed will do this. Here is the best sed tutorial I have seen:
http://www.grymoire.com/Unix/Sed.html

A crude method is more +num filename. This starts on line "num", and continues one page at a time until stopped

Thank you!

How about tail -n +36000000 <file> | head -n 5 ?

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And, if you're going to be doing this frequently, consider making the file a data base table indexed on row number, and printing the lines you need with a SQL query.
</edit>