Shell Script to start a program either not running or kill if running

avataratar · 03-29-2012, 03:18 AM

Hi Gurus,
I have alredy checked the forum but did not find exact match to my requirements.
I am looking for assistance in creating a script that does the following:
1. I need to pass the 2 arguments, one is user, other one system identifier.
2. if the 2nd letter of user contain "e" (not case sensitive), then proceed further. Otherwise exit.
3. If 2nd letter "e" match, then find the pid of program for that user because same server might running same program on 2 different user.
4. kill the program of the pid
5. check if completely killed the program of that user.
6. start the program for that user by doing the following command
setenv JAVA_HOME /usr/sap/<2nd argument>/java/jdk1.6.0_23
setenv PATH ${JAVA_HOME}/bin:${PATH}
either cd /usr/sap/<2nd argument>/SIC or SIC6.0/bin & ./run.sh &
or
/usr/sap/<2nd argument>/SIC or SIC6.0/bin/run.sh &
Thank you very much. All help appreciated.

EricTRA · 03-29-2012, 03:45 AM

Hello and welcome to LinuxQuestions,

This sounds pretty much like homework to me. If it is then you should know that we will not do the work for you. Check the LQ Rules to which you agreed when signing up:

Quote:

Do not post homework assignments verbatim. We're happy to assist if you have specific questions or have hit a stumbling point, however. Let us know what you've already tried and what references you have used (including class notes, books, and searches) and we'll do our best to help. Keep in mind that your instructor might also be an LQ member.

Even if it's not homework, you cannot expect us, who are all volunteers here, to do all the work for you. It all bottles down to:
Show us what you've got and where it's failing and we'll be glad to help.

Some good starting points:
Bash Guide for Beginners
Advanced Bash Scripting Guide

Looking forward to your participation in the forums. Have fun with Linux.

Kind regards,

Eric