Shell Script - Getting an argument from ps result
 

Hi,

I am writing a shell script, and want to get a specific argument from 'ps -ef' results. The order of arguments is different and awk (with column no) gives different values.

ps -ef | grep process
returns multiple processes with more than 50/60 unordered arguments each, but each process has a unique argument e.g. -Dwas.servername=WP_1

How can I 'ps -ef' so that I get values for -Dwas.servername for each process like below?

WP_1
WP_2
WP_3
...

Even the output like below will also be handy:

-Dwas.servername=WP_1
-Dwas.servername=WP_2
-Dwas.servername=WP_3
...

Thanks in advance,

Please try doing some searches of the archives and the web before you post your questions. This kind of thing comes up very often. In fact, I posted this for another user just a few days ago:

http://www.linuxquestions.org/questi...n-bash-921210/

sed and awk are the workhorse tools to use for extracting substrings from text. A sed command would look almost identical to the perl solution posted above, in fact.

Here are a few useful sed references.
http://www.grymoire.com/Unix/Sed.html
http://sed.sourceforge.net/grabbag/
http://sed.sourceforge.net/sedfaq.html
http://sed.sourceforge.net/sed1line.txt

Here are a few useful awk references:
http://www.grymoire.com/Unix/Awk.html
http://www.gnu.org/software/gawk/man...ode/index.html
http://www.pement.org/awk/awk1line.txt
http://www.catonmat.net/blog/awk-one...ined-part-one/

Also, as I mentioned in that previous thread, have a look at the man page for ps. It has a large number of options for formatting the output, and could simplify your requirements.

Thanks, Got the required output.
 

Hi, Thanks a lot, kbp. I got the desired output.
Thank you David also for sharing useful resources.