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Sending attachmeng using uuencode

Hai all,

RHEL AS 4

am using the below code to send attachment

[code]
cat mail_body;uuencode MED_HEALTHCHECKUP.OUT MED_HEALTHCHECKUP.OUT )|mailx -s "INVALID OBJECTS REPORT FOR $DATE_SUFFIX" knehealthcheck@gmail.com &
[code]

and it is failing with the below error
[code]
uuencode: command not found
[code]

I tried installing sharutils rpm as below
[code]
warning: sharutils-4.6.1-2.ia64.rpm: V3 DSA signature: NOKEY, key ID 1d1e034b
error: Failed dependencies:
rtld(GNU_HASH) is needed by sharutils-4.6.1-2.ia64
[code]

How I can fix this ?. if not, is there any other alternative other than uuencode as I also don't have mutt installed

Please advise

Kai

Have you considered saving yourself the trouble, and using mutt?

Code:

mutt -a MED_HEALTHCHECKUP.OUT -s "INVALID OBJECTS REPORT FOR $DATE_SUFFIX" knehealthcheck@gmail.com < mail_body

mutt should be available from the install DVD/CD.

Cheers,
Tink

Use mutt(1). It gets you MIME-compliance. Uuencoding attachments has arguably been superseded at this stage of the game.

P.S. RHEL4 support ended a couple weeks ago.

sendmail with attachment s

Dear all,

RHEL AS 4

am using the below code to send email as attachement

[code]
ALERTDIR=/reports/final
ALRMSG_SAM=$ALERTDIR/HEALTHCHECKUP.out
if [ -f $ALRMSG_SAM ]
then
rm $ALRMSG_SAM
fi

if test -s $ALRMSG_SAM
then
/usr/sbin/sendmail -t <<EOF
From: ERP-Production Server
To: testit@gmail.com
Subject: Health Check Report
Content-Type: html
content-disposition: attachment; filename=HEALTHCHECKUP.out
EOF
fi
[code]

This doesn't work and doesn't write in /var/log/mail too. but when am using the send mail in command line like

[code]
df -h | sendmail "testit@gmail.com'
[code]

works fine ?

Any idea ?

Kai

Quote:

Originally Posted by kais1 (Post 4635012)

Hi

probably you are using BASH, so the first thing in script should define which environment uses, like:

Code:

#!/bin/bash

echo "Hello, world."

then the IF clauses when testing variables could be more correct to use double quotes " around the var name, like:

Code:

if test -s "$ALRMSG_SAM"

then you can first try to break the code into smaller pieces to see what happens with this line:

Code:

if test -s $ALRMSG_SAM



I would try it this way:



TESTOUT=$(test -s "$ALRMSG_SAM")

if [ "$TESTOUT" ]; then

...

then you will see which part is having trouble so you can correct it. (probably you have read some of this or this)

good luck

Merged the two closely related threads. Please keep your discussions in one spot.