[SOLVED] sed - skip (or delete) first n line than continue

freeroute · 09-05-2017, 09:45 AM

Using sed, I would like to delete first n line from a file, than continue other commands.

I know

Quote:

sed 1,4d

, but its maybe not good for me, because I use complex command.

Quote:

sed 1,4d

means delete from 1st line to 4th line, than EXIT. I would like to delete the 1st 4 line, than continue....)

Now I use this commands:

Code:

sed -E 's/([a-zA-Z0-9.@]+):([a-z0-9._-]+@[a-z0-9.-]+\.[a-z]+{2,4}):([0-9]+.[0-9]+.[0-9]+.[0-9]+):(.*)/\1 \2 \3/' pix.txt | sed 1,4d | less

pix.txt first n line:

Code:

BY @xxxxxxx THE SUN GOES DOWN…
twitter.com/xxxxxxxxx

concat_ws(':',name,email,ip_address,members_pass_hash,members_pass_salt)
USER1:username@pixarra.com:00.00.149.106:0fb88e5bf21eddd113cdaff1e0f5cfa2:-yh#]
USER2:username@shasta.com:00.106.00.148:9225fdc2aed7e7c8b372d15e52486a73:0aUBr
USER3:username@comcast.net:00.163.00.62:46e3c1ed2f8ffbadcc0bcdb17a4afe1a:pbx]q

Thanks for your help.

Turbocapitalist · 09-05-2017, 11:59 AM

Perhaps you mean this?

Code:

sed -E -e '1,4d; s/([a-zA-Z0-9.@]+):([a-z0-9._-]+@[a-z0-9.-]+\.[a-z]+{2,4}):([0-9]+.[0-9]+.[0-9]+.[0-9]+):(.*)/\1 \2 \3/' pix.txt;

It will delete only the first four lines then process the rest with s///

freeroute · 09-05-2017, 12:05 PM

Quote:

Originally Posted by Turbocapitalist

Perhaps you mean this?

Code:

sed -E -e '1,4d; s/([a-zA-Z0-9.@]+):([a-z0-9._-]+@[a-z0-9.-]+\.[a-z]+{2,4}):([0-9]+.[0-9]+.[0-9]+.[0-9]+):(.*)/\1 \2 \3/' pix.txt;

It will delete only the first four lines then process the rest with s///

Thanks, it works.
I tried 1,4d without semicolon, with no success.

Quote:

-e

is important?

Turbocapitalist · 09-05-2017, 12:08 PM

No problem. sed is actually a programming language and 'd' is one of the commands. So is 's' So the semicolon is important to separate the individual commands.

Check the manual page

Code:

man sed

Using the -e to denote the script is a good idea if you start adding other options.