[SOLVED] Sed print only the line that exists two lines after the match

netpumber · 12-03-2014, 06:34 AM

Hello. I have this content in a file.

name: george
tag: genomes
ID: 455031

I want to get the line with the name by using sed/awk/grep.

I tried that command

sed -n '/455031/{g;1!p;};h' IDs.txt

which gave me the line with tag : genomes.

How can i make it to print only the line with name: george ?

Thank you.

grail · 12-03-2014, 08:42 AM

Why not save into the buffer when you hit 'name' and then when you hit desired result, swap the buffer and print the name.

netpumber · 12-03-2014, 02:12 PM

Sorry. That's my fault

The file contains more than one records of that type.

name: george
tag: genomes
ID: 455031
name: Tom
tag: genomes
ID: 455032
name: Mary
tag: genomes
ID: 455034
name: Jack
tag: genomes
ID: 455036

So i want to extract that info through ID

netpumber · 12-03-2014, 02:29 PM

Finally worked with awk

Code:

awk '{a[NR%3]=$0}/455036/{print a[(NR-2)%3]}' IDs.txt

syg00 · 12-03-2014, 05:28 PM

Relies on very structured data - and no blank lines for example. Why not something like

Code:

awk '{a[$1]=$0}/455036/{print a["name:"]}' IDs.txt

grail · 12-03-2014, 06:46 PM

And the sed solution I mentioned:

Code:

sed -n '/name/{h};/455036/{x;p}' IDs.txt