LinuxQuestions.org - [SOLVED] SED Guru Needed -- Combine Two SED Commands Into One Liner

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SED Guru Needed -- Combine Two SED Commands Into One Liner

I am trying to do in-place editing of each line that begins with the letter D, keeping the last 3 characters appended to the first 15 characters. I found separate sed commands to do the separate functions but cannot figure out how to combine them into a single command line:
# To remove everything except the 1st n characters in every line:

Code:

sed -r 's/(.{15}).*/\1/' file

# To remove everything except the last n characters in every line:

Code:

sed -r 's/.*(.{3})/\1/' file

Example -- I start with this inside "file":

Code:

D some text      end

Line that wont be edited because it does not begin with D

D other text    end

Other line that wont be edited because it does not begin with D

D similar text  end

I want to end up with this inside "file":

Code:

D some text    end

Line that wont be edited because it does not begin with D

D other text  end

Other line that wont be edited because it does not begin with D

D similar text end

I'm thinking it should be possible to combine the two sed commands but I have not been able to figure out how. Any SED Gurus out there to shed some light?

Thanks!!!

There are probably several ways to combine the two. If I understand the way you've described it, then one way would be like this:

Code:

sed -r -e '/^D/s/^(.{15}).*(.{3})$/\1\2/'

The initial /^D/ means to apply the following s/// only to lines starting with D

Do you want it to suppress printing of lines that start without a D? The above lets them pass through unmodified.

Hi Turbocapitalist. Thanks for the speedy reply!! Thats not working for me. Its not appending the last 3 characters. I am using grep to test the sed command:

Code:

grep ^D file |sed -r -e '/^D/s/^(.{15}).*(.{3})$/\1\2/'

Oh!! This is working!!

Code:

grep ^D file |sed -r -e 's/^D(.{15}).*.*(.{3})$/\1\2/'

THANKS Turbocapitalist!! ! ! !

No worries, but the grep is unneeded and probably in the way. The /D/ takes the place of grep and applies the substitution only matching lines. Try like mentioned above

Code:

sed -r -e '/^D/s/^(.{15}).*(.{3})$/\1\2/' somefile

It works with the test data you provided in the initial post.

If you want to eliminate lines that don't start with 'D' then you can throw in a conditional branch (t) to hop over a delete command (d) :

Code:

sed -r -e '/^D/s/^(.{15}).*(.{3})$/\1\2/;t;d;' somefile

Check the manual page a lot. It starts to make sense if you treat it as a simple programming language, which it is.

Code:

man sed