Script

blsimpson · 07-23-2012, 06:29 PM

Hello all,

I have a log file that looks like this:

Quote:

280898275 [org.springframework.jms.listener.DefaultMessageListenerContainer#0-1] INFO c.v.i.c.c.s.CardGenServiceImpl - generating VirtualCard
280952720 [org.springframework.jms.listener.DefaultMessageListenerContainer#0-1] INFO c.v.i.c.c.s.CardGenServiceImpl - Found Fundingcard com.xxxxxxx.xxxxxxx.transactional.FundingCard@15ffb1bd
280952737 [org.springframework.jms.listener.DefaultMessageListenerContainer#0-1] INFO c.v.i.c.c.s.CardGenServiceImpl - Completed generating VirtualCard
280952787 [org.springframework.jms.listener.DefaultMessageListenerContainer#0-1] INFO c.v.i.c.c.s.CardGenServiceImpl - Card controls stored for Virtual Card Hanlde :19096
280953126 [org.springframework.jms.listener.DefaultMessageListenerContainer#0-1] INFO c.v.i.c.c.s.CardGenServiceImpl - generating VirtualCard
281007859 [org.springframework.jms.listener.DefaultMessageListenerContainer#0-1] INFO c.v.i.c.c.s.CardGenServiceImpl - Found Fundingcard com.xxxxxxxx.xxxxxxx.transactional.FundingCard@3ad721b1
281007874 [org.springframework.jms.listener.DefaultMessageListenerContainer#0-1] INFO c.v.i.c.c.s.CardGenServiceImpl - Completed generating VirtualCard

The first part is the time in milliseconds. (I cant change this, I dont have access to the code for that.) What I need is to grep the file for "generating VirtualCard" take the number in the beginning and make it "variable a". Then grep for "Completed generating VirtualCard", take the number in the beginning, and make it "variable b". Once thats done, I need to take variable a and subtract it from variable b, and output the result. I just need the output.

What I am looking for is the amount of time it take for the card generation. Any help would be great, as I am not familiar with this..

antegallya · 07-23-2012, 06:53 PM

Hello

That should be as easy as

Code:

timeA=$(grep "generating VirtualCard" logfile | egrep -o "^[0-9]*")
timeB=$(grep "Completed generating VirtualCard" logfile | egrep -o "^[0-9]*")
echo Time elapsed : $(expr $timeB - $timeA)

antegallya · 07-23-2012, 07:20 PM

Well, I saw your log file actually has multiple generations of VirtualCard.
Do you need the generation time for each log entry ? If so, you could pipe your file to the following awk script :

Code:

#!/usr/bin/awk -f
BEGIN {
	start = -1;
}

/generating VirtualCard/ {
	if (start == -1) {
		start = $1;
	} else {
		print "Generations are not sequential !";
		exit 1;
	}
}

/Completed generating VirtualCard/ {
	if (start != -1) {
		print "Generated a VirtualCard in", $1 - start, "ms";
		start = "-1";
	} else {
		print "Bad log file";
		exit 1;
	}
}

blsimpson · 07-23-2012, 07:29 PM

That is correct, there are multiple entries in the same log file that I need the times for. I will try both of these options, and get back to you. Thank you so much!

antegallya · 07-23-2012, 07:35 PM

Okay, but note that first one won't work with multiple entries.

blsimpson · 07-23-2012, 07:37 PM

Oh, Okay. Will the second one loop through the whole file and output them all?

antegallya · 07-23-2012, 07:38 PM

Yes. That is what you want, right ?

blsimpson · 07-23-2012, 07:49 PM

Thats correct. Thank you so much!

blsimpson · 07-23-2012, 09:03 PM

Ok, I guess I dont know enough about this.. Can you point me in the direction on how I would accomplish what you said, pipe the logfile into the script..

antegallya · 07-23-2012, 09:16 PM

Once you've created the script and made it executable with chmod +x, you can pipe your log file as with any command

Code:

cat logfile | ./script

blsimpson · 07-23-2012, 09:24 PM

Thanks. I'm getting "Generations are not sequential !"

blsimpson · 07-24-2012, 12:13 PM

Thought I would check in and let you know where I got to. Using the code you gave me, I changed it a little, and came up with this:

Code:

#!/usr/bin/awk -f

BEGIN {
        start = 1;
}

/- generating VirtualCard/ {
        if (start < $1) {
                start = $1;
        } else {
                print "Generations are not sequential !";
                exit 1;
        }
}

/Completed generating VirtualCard/ {
        if (start != -1) {
                print "Generated a VirtualCard in", $1 - start, "ms";
                start = "-1";
        } else {
                print "Bad log file";
                exit 1;
        }
}

Gives me output of:

Quote:

Generated a VirtualCard in 1041 ms
Generated a VirtualCard in 1060 ms
Generated a VirtualCard in 1060 ms
Generated a VirtualCard in 1082 ms

Now to change them to seconds.

blsimpson · 07-24-2012, 01:14 PM

Ok, pass on the seconds.. Maybe someone can help me with this next part. I need to be able to write a script to loop through the log directory in sequence based on date, and write the output to a file. Example:

Directory:
~/test/
logFile.2012-06-04.log
logFile.2012-06-05.log
logFile.2012-06-06.log
logFile.2012-06-07.log
script.sh
generation.log

Command I am using:
cat logFile.2012-06-04.log | ./script.sh > generation.log

I could do them all manually, by just changing the date of the log file in the command, but I would like to be able to put other files in there, and have it pick them up as well. The log file names will always be logFile.YYYY.MM.DD.log

blsimpson · 07-24-2012, 01:35 PM

Using this seems to get me what I want:

Code:

#!/bin/bash

i=1
for file in /test/*.log
do
echo "$file" >> generation.log
cat $file | ./script.sh >> generation.log
# echo "File $((i++)) : $file"
done

Now to add some clean up, checking if the generation.log file exists, and if it does, move it to generation.bak.

Will continue to work through it

blsimpson · 07-24-2012, 01:49 PM

That was pretty easy. Added a simple if\then:

Code:

DATE=`date '+%m-%d-%y:%H:%M:%S'`
LOG=generation.log
LOGBACK=generation.$DATE.bak

if [ -f $LOG ];
then
        mv $LOG $LOGBACK
fi