LinuxQuestions.org - Script, display contents of a file using cat

This is the script I'm working on, I'm finished except for "displaying a file using cat" I'm unsure of the "wording". I know it's

Code:

cat filename

to view a file. I tried doing

Code:

echo "Enter a filename"

    cat $fname

    more $fname

I can't figure out what I missing.
I'm new to all of this and still tying too figure out all the commands. I would appreciate any insight you can give me.:)

Code:

#!/bin/bash

  leave=no

  while [ $leave = no ]

  do

echo Hello $USER

  cat <<++





          MAIN MENU

 1)  Print current working directory

 2)  Delete a file

 3)  Rename a file

 4)  List all files in a current directory

 5)  Display contents of a file

 6)  Edit a file

 7)  Copy a file

 8)  Move a file

 x)  Exit

++



  echo Please enter your selection $LOGNAME:

  read selection

  case $selection in

  1) pwd;;

  2) echo "Enter any $filename to be deleted"

    read f1

        rm $f1

          echo $f1" is deleted";;

  3) echo "Enter file to to rename"

    read f1

    echo "Enter new name of file"

    read f2

          mv $f1 $f2

          echo $f1" is renamed as "$f2;;

  4) ls -l;;

  5) echo "Enter a filename"

    read $fname

    more $fname

    ;;

  6) echo "enter any file to be edited"

      read f1

            vi $f1;;

  7) echo "Enter $filename to copy"

    read f1

    echo "Enter filename2 to be copied"

    read f2

            #cat $f1 > $f2

                cp $f1 f2

                echo $f2" is copied from "$f1;;

  8) echo "Enter $filename to move"

    read f1

    echo "Enter filename2 where to be moved"

    read f2

          mv $f1 $f2

        echo $f1" has been moved";;

  x) exit;;

  esac

  done

  Exit 0