Replace second character instead of first

Drigo · 10-24-2012, 09:37 AM

Let's say I have files like:

123_abc_as656512.txt
123_abd_as65612.txt
123_abe_as16562.5txt
123_abf_as1542.txt
123_abg_as131232.txt
123_abh_a123s12.txt

I want to replace them with

123_abc
123_abd
123_abe
123_abf
123_abg
123_abh

So essentially look for the second "_" and replace everything after that with nothing.

I was looking at something like this:
for FILE in <loop in the folder>
do
FILER=${FILE//_*} #Though this will get rid of everything after the 1st "_" character

done

any help??

pixellany · 10-24-2012, 12:48 PM

Code:

#!/bin/bash

for FILE in *; do
     NU=$(echo $FILE | sed -r 's/([^_]*_[^_]*).*/\1/')
     mv $FILE $NU
done

Drigo · 10-24-2012, 01:25 PM

Thanks I'll try that

jv2112 · 10-24-2012, 06:33 PM

Another option

Code:

#! /bin/bash

for file in ls . # This assumes you are running in the directory where the files are. 
do
cp -v "$file" ${"$file";0;7} #Copy the original to a new name.This starts from position 0 in the string and takes the first 7 characters
done                      # After confirming that is what you can want you can use mv to move vs. cp to copy.

chrism01 · 10-24-2012, 06:40 PM

Another option

Code:

echo 123_abc_as656512.txt|cut -d'_' -f1,2
123_abc

grail · 10-25-2012, 09:19 AM

Is there a reason we can't just use:

Code:

for f in *.txt
do
    mv "$f" "${f%_*}"
done