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Old 11-24-2017, 08:54 AM   #1
gaetan321
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Registered: Nov 2017
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remove duplicate results from a grep


grep returns

notification_interval 60
notification_interval 60
notification_interval 60
notification_interval 30
notification_interval 120
notification_interval 120

How would I remove the duplicate results ?

notification_interval 60
notification_interval 30
notification_interval 120

I tried using a combination of options with uniq but it still returns duplicates
grep notification_interval /usr/local/centreon/filesGeneration/nagiosCFG/1/serviceTemplates.cfg | uniq -d

notification_interval 60
notification_interval 60
notification_interval 120
notification_interval 60
notification_interval 180
notification_interval 180
notification_interval 90
notification_interval 30
notification_interval 60
notification_interval 30

Last edited by gaetan321; 11-24-2017 at 08:56 AM.
 
Old 11-24-2017, 09:01 AM   #2
TenTenths
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Pipe through sort before piping in to uniq
 
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Old 11-24-2017, 09:03 AM   #3
gaetan321
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Quote:
Originally Posted by TenTenths View Post
Pipe through sort before piping in to uniq
That makes sense. Thks
 
Old 11-24-2017, 09:16 AM   #4
MadeInGermany
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awk can remove duplicates without sorting
Code:
awk '/notification_interval/ && s[$0]++==0' /usr/local/centreon/filesGeneration/nagiosCFG/1/serviceTemplates.cfg
In this case you can even minimize resources by utilizing awk's word splitting
Code:
awk '$1=="notification_interval" && s[$2]++==0' /usr/local/centreon/filesGeneration/nagiosCFG/1/serviceTemplates.cfg
 
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Old 11-24-2017, 09:32 AM   #5
pan64
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yes, awk is a good solution (even grep is not required), but if you want to use sort, use sort -u and do not need to use uniq.
 
  


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