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Old 06-04-2009, 06:22 AM   #1
olegk25
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Registered: Jun 2009
Posts: 6

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regex or other solution to alter string fragment


please help!

I'm new to Linux and I'm looking for a regex (sed) or other simple way to format the SQL like

Code:
select ABREV from LIMITS, ABREV where ABREV='US'
into

Code:
select ABREV from SCHEMA.LIMITS, SCHMEA.ABREV where ABREV='US'
I've tried

Code:
sed 's/\(select.*from[ ]*\)\([A-Za-z0-9_]\)\(.*\)/\1SCHEMA.\2\3/'
but it produces only

Code:
select ABREV from SCHEMA.LIMITS, ABREV where ABREV='US'
any help please?

P.S. There may be any number of table names
 
Old 06-04-2009, 06:38 AM   #2
colucix
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Registered: Sep 2003
Location: Bologna
Distribution: CentOS 6.5 OpenSuSE 12.3
Posts: 10,509

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Try this awk code:
Code:
/select/{
 for ( i=1; i<=NF; i++ ) {
   if ( $i == "where" )
      break
   if ( to_sub )
      sub(/.*/,"SCHEMA."$i,$i)
   if ( $i == "from" )
      to_sub = 1
 }
}1
it checks for "from" and "where" words in the select statement and alter the embedded words accordingly. Awk cannot modify the input file on the fly, so you have to redirect the output to a new file:
Code:
awk -f test.awk infile > oufile
where test.awk is the awk script above.
 
  


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