Redirecting result of WGET to variable

mackowiakp · 07-22-2017, 01:17 PM

I want to redirect output of wget command to variable. WGET call needs user/pass authentication. I use /bin/sh not bash.

this is a part of my script:

Code:

/usr/bin/wget -O --http-user=$user --http-password=$pass "http://localhost:$port/json.htm?type=command&param=getuservariable&idx=1"

and the result is creation of file named "--http-user=username" and output on screen like this:

Code:

--2017-07-22 20:08:35--  http://localhost:8855/json.htm?type=command&param=getuservariable&idx=1
Resolving localhost (localhost)... 127.0.0.1
Connecting to localhost (localhost)|127.0.0.1|:8855... connected.
HTTP request sent, awaiting response... 401 Unauthorized

Username/Password Authentication Failed.

But if I run the same command without "-O" parameter, it create file with correct result, so authentication was successful.
So, how can I place result of WGET to variable instead file with correct authentication?

Turbocapitalist · 07-22-2017, 01:33 PM

The -O option always needs a filename. If you leave it blank then it will take the next string as a file name. So if you want to send to stdout, you need to specify the filename as a dash.

Then to capture that output into a variable, you can use command substitution.

Code:

html=$(wget -O - --http-user=$user --http-password=$pass "http://localhost:$port/json.htm?type=command&param=getuservariable&idx=1")

echo $html

mackowiakp · 07-22-2017, 01:42 PM

THX !!! It works!