reading path from a text file using bash script

mksc · 06-27-2008, 02:51 AM

hi all

I have a text file which consist file names with complete path.
I want a script which takeout path of file one by one and store path in a variable and file name in other variable.

i am giving you some part of this text file:

/root/Documents/ListOfnts.ods
/root/Documents/NewCmpnDet.xls
/root/Documents/ComTstChkLst.ods
/root/Documents/compstat.ods
/root/Documents/PDF BOOKS/handbook.pdf
/root/Documents/200804A0/04042008944.jpg
/root/Documents/printer/steps.txt
/root/Documents/AC97/bus.h

with the help of script I want output like this
PATH=/root/Documents/
FILE=ListOfnts.ods

Thanks
MKSC

druuna · 06-27-2008, 03:21 AM

Hi,

You could use the basename and dirname commands to split directories from filenames. The first one (basename) will strip the dir part, the other one does the opposite:

Quote:

myPath="/root/Documents/ListOfnts.ods"

$ echo myPath
/root/Documents/ListOfnts.ods

$ basename $myPath
ListOfnts.ods

$ dirname $myPath
/root/Documents

A simple onliner to show it in action, using your example:

Code:

$ for THIS in `cat infile`
> do
> echo $THIS
> DIRNAME=$(basename $THIS)
> echo $DIRNAME
> FILENAME=$(dirname $THIS)
> echo $FILENAME
> done

/root/Documents/ListOfnts.ods
ListOfnts.ods
/root/Documents

/root/Documents/NewCmpnDet.xls
NewCmpnDet.xls
/root/Documents

/root/Documents/ComTstChkLst.ods
ComTstChkLst.ods
/root/Documents

Hope this helps.

colucix · 06-27-2008, 03:25 AM

You can either use the dirname and basename commands into a loop which reads the file line by line, or use the following parameter substitution:

Code:

P=${line%/*}
F=${line##*/}

where $line is the current line read from the file.

An aside note: don't use PATH as name of a variable in your script, since it is a reserved word for the environment variable PATH. If you change its value inside your script, most likely you will get "Command not found" errors for subsequent statements.