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Old 07-06-2017, 01:43 AM   #1
MahendraL
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Printing a number in standard thousand format using printf


Hi,

Please see the C program below.

#include <stdio.h>
#include <stdlib.h>
#include <locale.h>

int main (int argc, char* argv[])
{
setlocale (LC_ALL, "");
printf ("%'llu\n", strtoull("109488", (char**) NULL, 10));
return 0;
}

When it's compiled and run on a Redhat 6.6 Linux machine, the output is
109,488

When it's compiled and run on a Ubuntu 14.04.3 LTS machine, the output is
1,09,488

Could someone please tell how can I get the 1st output (109,488) on the second machine (Ubuntu) ?

Thank you.
 
Old 07-06-2017, 02:40 AM   #2
grail
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Please use [code][/code] tags around your code

What happens when you use the same printf at the command line?
Code:
$ printf "%'llu\n" 109488
109,488
Could be your locale settings on the Ubuntu machine.
 
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Old 07-06-2017, 02:50 AM   #3
aragorn2101
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Check if the LC_ALL variable is set on both machines. Check this out: https://wiki.archlinux.org/index.php/locale
 
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Old 07-06-2017, 10:58 PM   #4
MahendraL
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Quote:
Originally Posted by grail View Post
Please use [code][/code] tags around your code

What happens when you use the same printf at the command line?
Code:
$ printf "%'llu\n" 109488
109,488
Could be your locale settings on the Ubuntu machine.
At command line, the printf printed 1,09,488 i.e. the same as the C program.
Somehow I found that if I add
setlocale(LC_NUMERIC, "en_US.UTF-8");
to my C program, then it prints the number in desired thousand format.
Thanks grail.
 
Old 07-07-2017, 02:05 AM   #5
grail
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Gald you found your solution Please remember to mark the question as SOLVED.
 
  


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