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mightyh

05-06-2014 12:15 PM

print value from offset row with bash

I have a command that provides system config info for each volume. I am trying to query a file containing the information for each volume, search out a volume group and respond with the associated volume. So basically

if the associated volume group = x then print volume name.

Code:

Volume name:                  2



Volume status:                Optimal

Thin provisioned:              



Capacity:                      ##### GB

Volume world-wide identifier:  

Subsystem ID (SSID):          

Associated volume group:      4

RAID level:                    



LUN:                          

Accessible By:                



Drive media type:              

Drive interface type:          

Tray loss protection:          



Secure:                        



Data Assurance (DA) enabled:  



Preferred owner:              

Current owner:                







Volume name:                  5



Volume status:                Optimal

Thin provisioned:              



Capacity:                      ##### GB

Volume world-wide identifier:  

Subsystem ID (SSID):          

Associated volume group:      5

RAID level:                    



LUN:                          

Accessible By:                



Drive media type:              

Drive interface type:          

Tray loss protection:          



Secure:                        



Data Assurance (DA) enabled:  



Preferred owner:              

Current owner:

grail

05-06-2014 01:51 PM

Sounds like a great idea ... so what have you done to solve the problem? Also, is the data shown the answer or what we are to start with?

Please also place code / data in [code][/code] tags to make it more readable.

mightyh

05-06-2014 03:14 PM

That is a sample of the data that i am trying to parse. I will turn the solution into a variable "$volumename" for another function.

I have a basic understanding of awk so i can definitely find the line with associated volume group but i am at a loss on how to print the volume name from 8 rows up.

This will find the line with volumegroup 1 and print it. But what i need is to print the volume name.

Code:

volumegroup = 1

awk -v volumegroup=$volumegroup -F":" '$1 ~ /volume group/ && $2 ~ volumegroup {print}'

grail

05-07-2014 07:29 AM

So why not store the volume name as you come across them and then when your expressions are correct you can print the saved value

mightyh

05-08-2014 05:36 PM

I would be grateful if you would show me how to do that, or point me to an existing thread.

grail

05-09-2014 02:51 AM

Same idea as what you have already done, simply add something like the following to the start:

Code:

$1 = "Volume name"{vname = $2}

To get just the name, seeing as there is a good deal of white space everywhere, I would add this to your separator so it is absorbed:

Code:

-F": *"

If there are tabs in there as well you will need to alter to suit

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