Have output in the below format.
The paterrn(HeartBeat) is searched in file of multiple directories.
Now wanted to print the files which has many occurrence of the pattern. if the pattern count crosses 10, let it print the file , otherwise not

egrep -i -c "HeartBeat" /export/acdba/ac/data/workdir/batch/*20160705*/jobdef.log

/export/acdba/ac/data/workdir/batch/dir1/jobdef.log:2
/export/acdba/ac/data/workdir/batch/dir2/jobdef.log:1
/export/acdba/ac/data/workdir/batch/dir3/jobdef.log:1
/export/acdba/ac/data/workdir/batch/dir4/jobdef.log:1
/export/acdba/ac/data/workdir/batch/dir5/jobdef.log:46
/export/acdba/ac/data/workdir/batch/dir6/jobdef.log:8
/export/acdba/ac/data/workdir/batch/dir7/jobdef.log:19
/export/acdba/ac/data/workdir/batch/dir8/jobdef.log:2
/export/acdba/ac/data/workdir/batch/dir9/jobdef.log:5
/export/acdba/ac/data/workdir/batch/dir10/jobdef.log:1
/export/acdba/ac/data/workdir/batch/dir11/jobdef.log:1
/export/acdba/ac/data/workdir/batch/dir12/jobdef.log:1
/export/acdba/ac/data/workdir/batch/dir13/jobdef.log:3
/export/acdba/ac/data/workdir/batch/dir14/jobdef.log:1
/export/acdba/ac/data/workdir/batch/dir15/jobdef.log:24

so you need to filter the result
I would suggest you to use awk, use : as field separator

Or you could feed it to a while loop ... really the options are pretty endless

Print the whole file? to standart output, on paper?

to standard output

just the file names

I have to say, I am a little curious at the example output based on your grep statement. You have *20160705* in the path but your output has dirN at he same point in the path?

Don't forget to show us what you have tried and we will help where you are stuck?