password snchronization script
I have written a shell script which replaces the password of a user in File2 if that user is also present in File1.Following are the contents of two files
File 1 palanspu:3aLdJ8mtCEXJI,A/SS:24563:/usr/bin/ksh rahul:7j6Zm/48.6rs,A/1S:24669:/usr/bin/ksh File 2 rahul:ydMaodGCHIzxU,A/jN:25100:/usr/bin/ksh anukul:YX6UQQl6OpSaU,A/US:25112:/usr/bin/ksh The script is as follows #!/bin/bash #creates array of passwords from File1 pass1=`cut -d ":" -f2 first` cnt=0 if [ -s tmp-sec ] ; then rm tmp-sec else touch tmp-sec fi for usr1 in `cut -d ":" -f1 first` ; do sed -e "/^$usr1:/ s/:.*$/:${pass1[$cnt]}/" sec >> tmp-sec cnt=$(($cnt+1)) done After executing the shell script the output is taken in the file tmp-sec. But I get the error as follows and also the contents of tmp-sec file is not as expected $ sh temp.sh sed: Function /^palanpsu:/ /:.*$/:3aLdJ8mtCEXJI,A/SS cannot be parsed. $ cat tmp-sec rahul: anukul:YX6UQQl6OpSaU,A/US:25112:/usr/bin/ksh $ I have to synchronize the password only using the shell script and by no other way?Can anyone help? |
Have you tired to use awk instead of sed?
Example: awk -F: '{print $2}' would give you the field you want... |
plz tell me how can I use awk to synchronize passwords
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