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Need help for basename

I have tried to run this:

Lets say i have two files in the current folder:
file1.xyz
file2.xyz

Quote:

$find . -name "*.xyz" | xargs basename -s ".xyz"

i was hoping to get

Quote:

file1
file2

but this is the output i got

Quote:

basename: invalid option -- 's'

this is the version of basename i have

Quote:

$basename --help
Usage: basename NAME [SUFFIX]
or: basename OPTION
Print NAME with any leading directory components removed.
If specified, also remove a trailing SUFFIX.
--help display this help and exit
--version output version information and exit
Examples:
basename /usr/bin/sort Output "sort".
basename include/stdio.h .h Output "stdio".

Report basename bugs to bug-coreutils@gnu.org
GNU coreutils home page: http://www.gnu.org/software/coreutils/
General help using GNU software: http://www.gnu.org/gethelp/
For complete documentation, run: info coreutils 'basename invocation'
[khorseik@ntu03 output]$ basename --version
basename (GNU coreutils) 8.4
Copyright (C) 2010 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later http://gnu.org/licenses/gpl.html.
This is free software: you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.

Written by David MacKenzie.

The 8.4 version of basename does not support the "-s" option.

Code:

DESCRIPTION

      Print NAME with any leading directory components removed.  If

      specified, also remove a trailing SUFFIX.



      Mandatory arguments to long options are mandatory for short options

      too.



      -a, --multiple

              support multiple arguments and treat each as a NAME



      -s, --suffix=SUFFIX

              remove a trailing SUFFIX; implies -a

....

....



GNU coreutils 8.26              January 2017                      BASENAME(1)

What does this give you:

Code:

find . -name "*.xyz" -exec basename {} .xyz \;

TenTenths example should work as your own output gave the exact same example:

Code:

basename include/stdio.h .h Output "stdio".

Quote:

Originally Posted by TenTenths (Post 5653843)

What does this give you:

Code:

find . -name "*.xyz" -exec basename {} .xyz \;

Yes, this one works as what i want. But the problem, i need to use xargs as part of my next step of work.
So i guess i would need to find a workaround with the -exec

You can use find with xargs. Leave out the -exec clause and use -print0 instead. Then for xargs use -0 or --null.

Be sure to check the manual pages for both periodically so that they start to become familiar.

Code:

man find

man xargs

Edit: see also the manual page for basename and the -a option.

you may find this http://www.thegeekstuff.com/2013/12/xargs-examples/ useful (or you can find similar pages too)

Quote:

Originally Posted by Turbocapitalist (Post 5654227)

Code:

man find

man xargs

Edit: see also the manual page for basename and the -a option.

You can, but you shouldn't.
http://mywiki.wooledge.org/UsingFind...and_-exec_.2B-

Quote:

Originally Posted by nodir (Post 5654418)

You can, but you shouldn't.
http://mywiki.wooledge.org/UsingFind...and_-exec_.2B-

Right. Re-read post #8 where -print0 is mentioned for find and --null mentioned for xargs

Oh, i read that.
And truth to be told: i am not that much in the subject that i could advise or explain it at all.
My post was rather focused at the OP, so he knows that some folks have strong opinions against usage of xargs ( while, like said, i for one sure can't say much about it).

in short: it really was a side-note only.

jrffrey
why are you using a old operating system from 2010
courutils 8.4 is 7 years old
http://ftp.gnu.org/gnu/coreutils/?C=M;O=D

Red Hat Enterprise Linux 6 is fully supported until November 30, 2020, and uses coreutils-8.4. A lot of people are using it.